List customer and product without sales hackerrank sql server oracle. You signed out in another tab or window.

List customer and product without sales hackerrank sql server oracle I tried below query and it worked for me. We use cookies to Link to SQL Code on GitHub: The goal of this project is to analyze data from a sales records database for scale model cars and extract information for decision-making. No need to get emotional about it. [Y]. - adminazhar/-hackerrank-SQL-intermediate-skills-certification-test-solution Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. I'm trying to calculate the total purchase amount of each customer from the database available online on W3 Schools. schema_id)+'. They are essential for building more sophisticated and robust queries, managing data relationships, and optimizing query performance. with gen as ( select 1 as cust_id, (date '2020-01-10') + 1 as q from dual union all select 1, (date '2020-01-10') + 2 as q from dual union all select 1, (date '2020-01-10') + 3 as q How can we rewrite this SQL query without IN clause [also without rownumber concept in use], as ORACLE is having restriction for IN clause. At first I thought I'd just generate the tables in Oracle as SQL, manipulate the data formats, and run the query in SQL Server. If we want to find the total count of sales for each month (instead of the total sales amount), replace the This T-SQL query SELECT city, Len(city) FROM station ORDER BY Len(city) returns table sorted by city, not by Len(city) - is this proper behavior? Hackerrank SQL challenge. This collection provides solutions to the HackerRank SQL Certification Test problems. rfm, tg. InvoiceTotal FROM dbo. city_name ) SELECT SQL Server Oracle; CREATE TABLE products_sold ( product_id numeric(10) not null, customer_id INT not null, CONSTRAINT fk_pr FOREIGN KEY (customer_id) REFERENCES customer(id) ) GO. Based on his total column, I've added the Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. 06%. Download Sample Files. ORDER_DATE <= DATEADD(year, 10, (SELECT MIN(ORDER_DATE) FROM ORDERS)) ORDER BY O. month and now that i think of it SQL Server 2005 has You signed in with another tab or window. – Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. fn_table_numbers( numini integer, numfin integer, exponencial integer default 0 ) return tbl_numbers is numeros tbl_numbers; indice number; begin numeros := tbl_numbers(); for i in ( with tabla as (select numini, numfin from dual) select numini num from tabla union all select You'll have to omit those records in the addition which don't belong to a full week. So, prior to summing up, you'll have to find the min and max of the dates, manipulate them such that they form "whole" weeks, and then run your original query with a WHERE that limits the date values according to the new range. TransactionDate, I. The total column was done by a friend and works as expected. Below are seven examples of the kinds of problems a data scientist or software engineer might face during a technical interview. be/35gj How can I achieve the following in oracle without creating a stored procedure? Data Set: question_id element_id 1 7 1 8 2 9 3 10 3 You signed in with another tab or window. SQLSyntaxErrorException: ORA-01795: maximum number of expressions in a list is 1000 for above expression. Step 1: Install Oracle ODBC drivers on server. id group by c. Clarification: I want a row for each possible month/product tuple. In general, I would not suggest using these legacy views unless you absolutely need to backport your These concepts introduce more complex features and functionalities of SQL. There are many factors that determine how the database resolves the query, object statistics, SYS schema statistics, and parameters, as well as server performance. Fund open source developers The ReadME Project. the basic idea is to exploit oracle's hierarchical queries. No, in Oracle there is no SELECT without FROM. units_sold, this_month. id NOT IN (SELECT product_id FROM invoice_item); ----- Products Product GitHub Copilot. SELECT Customer , Month , COUNT(ReceiptNo) AS Visits , SUM(Revenue) AS Revenue FROM (SELECT customer_first_name || ' ' || customer_middle_initial || '. * FROM tbProduct a INNER JOIN ( SELECT Category, MAX(Price) maxPrice FROM tbProduct GROUP BY Category ) b ON a. The columns are: Customer name, Year, Month, and Revenue. Solve Challenge. ' || I linked ORACLE Database in my local sql server called X. year in (2008,2007) group by fill. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. - Id - Customer. line_total_price), 2) as tot from city ci, customer cu, invoice i, invoice_item ii, product pr where ci. id INNER JOIN Customer CU ON CU. category = b. I could set this query up in one Oracle database and make it run slow and make it run fast in another. coalesce is supported in both Oracle and SQL Server and serves essentially the same function as nvl and isnull. changing the where clause to where rnk <= 5 would list top 5 selling products per city. I've not used SQLfiddle much so I wasn't able to setup a test schema for this (yet). customer_ID GROUP BY customer_table. Try this:-- custom table information select schema_name(t. SQL (Basic) SQL Product Actions. Data Two tables: Customers and Orders. My current query gives me the product wise purchase amount for the customer. select d. SQL : Select the latest sale for each product. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; SQL Server: Show a list of Customers that have more Orders than a specify Customer. What sql query would return the monthly sales per product, and include products with no sales? (I'm using sql server if that makes any difference). (SELECT *, 'Top 10' FROM sales ORDER BY sales_amount DESC LIMIT 5) UNION (SELECT *, 'Bottom 10' FROM sales ORDER BY sales_amount ASC LIMIT 5) ORDER BY sales_amount DESC; which gives the required result, without CTEs. Query: SELECT s. Customers also increase uptime for Oracle applications by running them on any Oracle server and Java applications run 2X faster on Oracle SPARC servers using unique, built-in accelerators. ora file, it's not going to know the List Customer And Product Without Sale In One List Return, All Customers Who Do Not Have An Invoice And All Products That Were Not Sold. 700 Similarly, 2001(Year), 2002(Year),2003(Year) also contains number of sales. You signed in with another tab or window. SELECT first_name from customers WHERE first_name not in (select first_name from customers join orders on customers. quantity), 0) as quantity from customer c cross join product p left join invoice i on c. I am trying to generate results that show all customers that are in the customer table that have never placed an order and will therefore have no entry on the invoice table. [SQL] Using Oracle in HackerRank question, largest and smallest city name. product_name, ROUND(sum(ii. Top Competitors. Use The UNION Operator In This Query. Invoice I INNER JOIN dbo. Note: Print NULL when there are no more names corresponding to an occupation. The above logic works with or without time components. challenge_id" could Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI here's some code that should work in SQL Server, Oracle, or MySQL: SELECT current_timestamp - CAST(d1. you have to specify a maximum length of the list (100 in the sample query below). Automate any workflow Solution for some HackerRank challenges by SQL Server. You signed out in another tab or window. The problem is that customer 102 only has 1 order (both records are orderId 9), but this subselect will treat customer 102 as having 2 orders. product_name FROM product WHERE product. This repository contains MySQL solutions of the HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test. Ask Question Asked 7 years, 10 Line 12 Invalid column name 'challenges_created'. QNTY FROM CUSTOMER_T CUST, ( The question title is not very helpful. Medium SQL (Intermediate) Max Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. Customer) totalOrders, COALESCE(SUM(b. rownum_rf, count(*) count_rfm, Users select their countries from a list I give to them, but the list is really huge so it would be great to have a SQL query that can avoid using that list, that is look in the DB and give back only those countries which are in the database, because for example I have nobody from Barbados, even if I have that option in the country select field Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. product_id; Output: Consider two non-negative long integers, and , where . List the top 1 customer's transactions who have the highest total transaction amount in such a way that the result shows all the transaction done by the customer and the last row shows the total amount of all the transaction done by the customer. sql hackerrank sqlserver hackerrank-solutions hackerrank Code Issues Pull requests Códigos em SQL (Oracle e MS Server), para aprendizado e referência. Customer GROUP BY a. sales and see if those three sales numbers are correct. sku, product. List Customer and Product Without Sale Using the UNION operator, in one list return all customers who do not have an invoice and all products that were not sold. But let say I only want to show the the city/cities where someone has done at least 2 orders, and that there are two customers living in this city/cities, so what I want to do is to pick out the city/cities where a customer has made at least 2 orders, but then show the Actions. Automate any workflow Oracle schemas are like My Documents folders in the Windows OS. MS SQL Server's schemas are namespaces. [PS]. ________ I have got the query working to pull customers monthly revenue from all the years for which the data is present. It will be updated everyday. This repository contains all solutions and "thought process" to Hackerrank's SQL challenges. Ask Question Asked 7 years, 10 months ago. I had to write a particular query in a framework that write query by itself. invoice_id = i. select am, rf, rfm, count_rf, count_rfm, rownum_rf, rownum_rfm from ( -- next join the top 10 products to the data again to get -- the subproduct counts select tg. New Companies. I was not able to solve it at all. product_name, Coalesce((ii. sql and 2. Submissions. Question 1: Which products The following is a much better solution to the problem: WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN NAME END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' The company president would like the sales listed starting with the highest amount first. Watch also my other videos for more SQL Certification Solutions. Orders. Again, this is a rank-without-ties query. The database is SQL Server 2008 R2. Curd Now, 2000(Year) contains number of sales. Create linked server on SQL server using System DSN. Focus on standard sql and you know enough for most companies . customer_name (category="customer") or product. TotalScore I have the following SQL statement that shows the total sales amount for customers in cities who have done at least 2 orders. Msg 4104, Level 16, State 1, Server WIN-ILO9GLLB9J0, Line 9 The multi-part identifier "Challeneges. Solved. A user can grant permissions to other users to see things in their schema but an Oracle schema is essentially a user's workspace. 0. This is a new question Hackerrank has added for the advance level SQL certification. columns t2 on t2. product_name (category="product") Tables: Customer. country_name,CI. You need to make sure that the Data Source is an alias that the tnsnames file knows about (on the server where SQL Server resides, regardless of where you're running the queries from); SQL Server is going to be just like any other Oracle client and needs to know where to connect to and without the tnsnames. _____ SUBSCRIBE!Do you want to understand how to solve SQL My journey of earning a SQL certification and tackling HackerRank SQL challenges. I have an Oracle 11g XE database that I would like to transfer into SQL Server Express 2005. ID, a. Reload to refresh your session. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. name = 'MyTableName' -- table columns information select schema_name(t. I need a query that will list the total spent on both hair cuts and products for each customer in the customers table. Input Format The Employee table containing employee data for a company is described as follows: You can use two window functions to calculate difference between consequtive dates and sliding window with ROWS offset to count distinct preceiding consequtive days. Basic Join. Butter 3. Explore my GitHub repository to learn from my experiences and find Let's say we have a Product table (product_id, product_name) and a Sales table (product_id, date, qty, amount). Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. This article talks about performing relational division in SQL in great detail and helped to clear things up a lot for me, Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; Oracle Setup: CREATE TABLE sales ( "DATE", Store, Sales ) AS SELECT DATE '2015-01-01', 'St01', 12123 FROM DUAL UNION ALL SELECT DATE '2015-01-01', 'St02', 3123 FROM DUAL UNION ALL SELECT @VasinYuriy That is not a limitation of the SYS. There are several basic variations between Oracle and SQL Server Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. 1. Google SQL Interview Question:https://youtu. By detailing sales figures per city and identifying customers who spent 25% or less than This works for Oracle PL/SQL. com; Oracle ERP Cloud SQL Query to find Bank SELECT a. a. sql. Need to get MAX selling price in last 4 transaction. Binary Tree Nodes. Milk 2. id group by The only one's this question deals with is the Customers table (stores customer details), the ProductSales table (store details about each product sale, and HairCuts table, store details about each cut. : enclosed in parentheses). product_id = p. The return type for isnull matches the type of the first argument, that is not true for coalesce, at least on SQL Server. Medium SQL (Intermediate) Max How to Earn SQL (Advanced) Certification on Hackerank ? In this video, you'll learn how to earn free certification from Hackerrank*****Impor This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. Return 3 Values: - Category - Is This Line Related To "Customer" Or "Product"? Print "Customer" Or "Product" Without Quotes. Once upon a time, dual had two records (hence the name) and was intended to serve as a dummy recordset to duplicate records being joined with. PRICE FROM CUSTOMERS C INNER JOIN ORDERS O ON C. It then orders them by the number descending and chooses the first row -- the customer with the most orders. We use cookies to ensure you have the best browsing Try this one if you want to get the whole row, (supports most RDBMS)SELECT a. OrderDetails. Now, Now, the question is to find the product with highest number of sales. Id (Category="Customer") Or That documentation suggests that the command only has effect when executing a statement at the SQL*plus prompt. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions SQL. But you need to add a terminating / after your code, on a line on its own - Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; T-SQL Challenges from hackerrank. Considering your data model and requirements, you should try the below SQLs. product_name FROM Sales s JOIN Products p ON s. Using the UNION operator, return a si the following solution for oracle is adopted from this source. Depending on the employer’s technical interviewing tool, candidates can choose from a range of relational database tools, including DB2, MySQL, Oracle, and MS SQL Server. What I need is the total purchase amount. Name, COUNT(b. Oracle is the only technology provider with a complete suite of integrated cloud applications and a cloud infrastructure platform. Leaderboard. id (category="product") Name: customer. Please check 1. Getting java. Time components can cause the code to do things you don't expect. digit as int) FROM ( SELECT digit FROM ( select '1' as digit union select '2' union select '3' union I had a simil issue. id GROUP BY CO. ProductID LEFT JOIN I believe the following query should work to identify the customer name with the highest amount derived from all orders in the current calendar year:. Concat is an SQl server function that takes a variable number of string arguments and concatenates (JOIN) them into a single string. Sql skills are transferrable across most databases. Customer_spending. CustomerID GROUP BY CustomerID HAVING COUNT(*) > 1) And another way for SQL Server 2005+: Below is the code in a SQL statement for SQL Server. Example here:. id (category="customer") or product. id and ii. I can list them all but not just the ones I want, might not understand Rank(), ROW_NUMBER(), FIRST_VALUE use in Oracle. Unsolved. The result is ordered by The easiest way would be to specify. Please check 1. customer_name, p. 1. '+t. Customers achieve breakthrough performance, cost efficiencies, and security for business-critical workloads with Oracle servers. 7. country_name, Ci. CustomerID = C. Oracle also has a number of legacy data dictionary views-- TAB, DICT, TABS, and CAT for example-- that could be used. (There are some important differences, coalesce can take an arbitrary number of arguments, and returns the first non-null one. - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Without Sales(solution-1,2). invoice_id and ii. The physical and logical storage methods for IMAGE and TEXT data differ from Oracle to Microsoft SQL Server. This is appears to be a query that can be solved with relational division and one way to achieve that is by utilizing nested NOT EXISTS queries. 1 SQL Query and Information about Sales Order Line Number ; Oracle Script to Copy Responsibilites of one user account to another user account Emails generated by Oracle ERP are delivered to customer/Supplier with from email address as “no-reply@oracle. List all the customer IDs and last names who have made more than 2 orders. id=orders. Medium SQL (Intermediate) Max Score: 30 Success Rate: 97. - mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Customer Stories Partners Executive Insights Open Source GitHub Sponsors. The query should return all customers ,even customers without invoices and also products,even those products that were not sold. customer_ID, customer_name HAVING COUNT(DISTINCT product_ID) > 10 Verify your SQL Skills. product_name, coalesce(sum(ii. lstid , t. While you can have Accounting and Marketing schemas, they are not tightly-coupled to individual users. 99%. For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S). Question Find customers who have never made an order. WITH CTE AS( SELECT DISTINCT CO. Oracle SQL specifically. Accelerate your Job Search. Hopefully it's not a big difference but I suspect at least the CASE statement isn't the same on Oracle. sql sql-server hackerrank sql-query sqlserver So, after reading some other materials and trying a few different things, I think I have a correct query. – How to Earn SQL (Advanced) Certification on Hackerank ? In this video, you'll learn how to earn free certification from Hackerrank*****Impor In standard SQL, you would write: SELECT customer_num, COUNT(*) FROM AllOrder GROUP BY customer_num ORDER BY COUNT(*) DESC FETCH FIRST 1 ROW ONLY; This aggregates the data by customer, counting the number of orders. Discussions. nb: using dense_rank also allows for "top n per" result, e. customer_id and i. com” instead of no-reply@client-DomainName. Please append a semicolon "" at the end of the query. The syntax for foreign keys is the same in Oracle and SQL Server. By detailing sales figures per city and identifying customers who spent 25% or less than the average, this solution aids in strategic decision-making for optimizing sales and customer engagement. SELECT c. sales, last_month. Order by Sales Data for all customers and products. customer_id LEFT JOIN invoice_item ii ON ---- Products Without Sales (solution_1) SELECT product. : the name attribute) from the Employee table in alphabetical order. Input Format. Get certified with hakerrank SQL Interme You signed in with another tab or window. id = i. Contribute to ejaj/SQL development by creating an account on GitHub. Learn more about Foreign Keys. In other words, I want to select all customers from the customer table where there is no entry for their customer number in the invoice table. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; I can do this on a calculator without any problems but writing the SQL is a different story. , This is a SQL query to get the total amount spent on each product in each city. Don't use BETWEEN on dates. object_id = t. all_columns -- In this video we will discuss an SQL interview question that was asked in meesho's HackerRank online test. Medium SQL (Advanced) Max Score: 40 Success Rate: 93. Business Expansion. You can easily perform UNION with both the SQLs. * from sys. Find and fix vulnerabilities Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test 🎓. 50%. Welcome to CarrY4U Product GitHub Copilot. NAME, O. cust_id) Oracle Products, Solutions, and Services. In Microsoft SQL Server, a pointer to the IMAGE or TEXT data is stored with the rows in the table while the IMAGE or TEXT data is stored separately. g. ProductID = P. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. GitHub - MahedeiHasan/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions: Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. SELECT Distinct Name FROM Production. Example 1 without empty rows: product ,year ,month from sales --this ideally would be from a products table cross join tm where year in (2008,2007)) fill where fill. For example, if and , the calculation is . create or replace function [schema]. customer_id left join invoice_item ii on ii. am, tg. The OCCUPATIONS table is described Contains solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test 🎓. We then apply SUM() to calculate the total sales for each month, and group the results by year and month. The EMPLOYEES table and the SALES_DEPT table contain the following columns: The customers should be listed alphabetically beginning with the letter 'A', and their corresponding order totals should be sorted from the highest amount to the lowest amount . sales, last_year. Note: Print NULL when there are no more names corresponding to an Given a sales table with sales amount stored in local currencies and an exchange rate table containing currency conversion rate, to get total sales amount in USD for each sales date I need query Ironically Oracle owns MySql. Business_expansion. Unzip the packages to a local directory on the SQL SQL query: SELECT Name_Seller, Month, Value FROM SALES WHERE Value = (SELECT MAX(Value) FROM SALES GROUP BY Name_Seller); List customers who sold most in mssql. This makes it portable to MySQL for example. ID = b. sql files for the solutions I submitted! I do not think this answer is correct, although it does produce the correct result. If you don't select DUMMY from it, it uses a special access path (FAST DUAL) which requires no I/O. 15%. Joining the subquery result to product table reduces the rows involved in that join. Create System DSN to Oracle database on SQL Server. ) This article analyzes the performance of different DAX techniques to identify any products without sales in an area or a time period. In neither of the solutions do you guarantee to generate the results with the correct ordering. Oracle isn't the problem Created an ODBC connection to the database on the Oracle server on this machine; Restarted MS SQL Server; Created a linked server (Microsoft OLEDB Provider for ODBC Drivers) in the SQL instance; When connecting to the SQL Server using sqlcmd on this machine (I did not install SSMS there), I can query the linked database using OPENQUERY(). ID WHERE O. name as TableName, TYPE_NAME(t2. All customers who do not have an invoice All products that were not sold Category: Is this related to "customer" or "product"? Print "customer or "product" ID: Customer. You can toss a subquery in your WHERE clause to find customers that have had sales today:. List all sales along with the corresponding product names. ORDER_ID = O. All the problems and theirs solutions are given in a systematic and structured way in this post. Given pairs of long integers, and , compute and print the bitwise AND of all natural numbers in the inclusive range between and . city_id = CI. This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. price = b. The Oracle Cloud offers all the services you need to migrate, build, and run your IT, from existing enterprise workloads to new cloud-native applications and data platforms. . Please note, each year contains number of sales that products has made. Using the dual table is a good practice. SELECT productid FROM product where purchase_date > sysdate-30; Remember this sysdate above has the time component, so it will be purchase orders newer than 03-06-2011 8:54 AM based on the time now. tables t where t. name as TableName, t. country_id = CO. object_id Here is the first solution, which could be used as a working base. The fact that Oracle has a feature that SQL Server does not seems to generate all kinds of reactions towards the disputable characteristics of this feature. Surprisingly it does seem to understand PL/SQL; and even more surprisingly it handles the set serveroutput on, which is a SQL\Plus/SQL Developer client command. sql sql-server oracle hackerrank oracle-database hackerrank Generate the contest leaderboard. digit + d2. Print Prime Numbers. sql files for the solutions I submitted! Hacker Rank SQL. SQL query for overview of purchased products per user. city_id and cu. city_name,COUNT(city_id) AS cnt , AVG(COUNT(city_id)) OVER() avg_cnt FROM COUNTRY CO INNER JOIN City CI ON CI. Name, S. 200 2. Customer C ON I. Problem. That is my criteria for which answers fall technically short. id = ii. Print NA for null customers or product or null quantity . [ In this video I am solving the intermediate Certification Skills Test on Hackerrank. 7 Advanced SQL Interview Questions. That site doesn't seem to ever show your the output from your submission, unhelpfully, but does with just 'run code'. Using the UNION operator, return a single list that includes all customers who do not have an invoice and all products that were not sold. Hacker_ID, H. Output the first name of the customer. Customers using Oracle Recruiting source better quality candidates, improve time to hire, and reduce recruiting expenses. Medium SQL (Intermediate) Max Score: 30 Success Rate: 96. First SQL returns this list –> All customers who do not Hello coders, in this post you will get all the solution of HackerRank SQL Solutions. From the MS docs "For stored procedures that contain several statements that do not return much actual data, this can provide a significant performance This query joins the Sales and Products tables on the product_id column, groups the results by product name, and calculates the total sales revenue for each product. It showcases my growth, challenges faced, and solutions offered. CREATE TABLE products_sold ( product_id numeric(10) not null, 2 List Customer and Product Without Sale Using the UNION operator in one list return all customers who do not have an invoice and all products that were not sold For each customer without an invoice return - the string customer - the customer id - the customer name 2 For each product without an invoice return - the string product - the product id - the product name 4 The Install Oracle ODBC drivers on SQL Server. 66%. customer_ID = orders_table. My solution: WITH MaxScores AS ( SELECT Hacker_ID, Challenge_ID, MAX(Score) AS MaxScore FROM Submissions GROUP BY Hacker_ID, Challenge_ID ), SummedScores AS ( SELECT Hacker_ID, SUM(MaxScore) AS TotalScore FROM MaxScores GROUP BY Hacker_ID ) SELECT S. tables t inner join sys. PSDBOWNER SQL SERVER Name: X I tried below query in my SSMS select * from [X]. Some editing is likely required to make it run on Oracle. The below makes two passes of the data, but returns correct results in each case. I need to use the Adventurewalks2017 database for thisagain. product_name; You're missing the ON keyword and there is the additional issue that in Oracle dates always have the components year, month, day, hour, minute and second and (assuming the NLS_DATE_FORMAT session parameter allows a valid cast from a string to a date) then '2017-12-31' will be converted to 2017-12-31T00:00:00 and your query will not select values that are SQL : List Customer And Product Without SaleTo Access My Live Chat Page, On Google, Search for "hows tech developer connect"I have a hidden feature that I pr Oracle supports the DATE keyword for introducing date constants using ISO-standard, unambiguous, non-locale-specific formats. it is wrong i Could you modify the first line of the select statement to: SELECT product, this_month. Sales. 300 3. SELECT count(*) /*count of transactions*/ FROM transactions WHERE /*Transactions in the last two months*/ transaction_date > DATEADD(mm, -2, GETDATE()) /*For customers that have had a sale today*/ customer_number in (SELECT customer_number List Customers and Products Without Sales Enter your query below. Seems to be a little bit simpler. i created an oracle function that returns a table of numbers. PRICE DESC I assume that you use SQL Server, this is why I use TOP 1. Customer Relationship Management (CRM) Information Technology We use both Oracle and Microsoft SQL Server for our entire product line, using the best features of each of them to solve SELECT TOP 1 C. I used the table (values('x')) DUAL(DUMMY) to retrieve the result from a query that has a single column with an ANY result (in bold what writes the framework, in italic what I put as parameter): SELECT CASE WHEN 'X' = ANY (SELECT COLUMN FROM TABLE) THEN 1 Explanation: In this query, we use the YEAR() and MONTH() functions to extract the year and month from the Order_date column. It focuses solely on offering correct answers for SQL queries, joins, and aggregations, helping users pass the certification efficiently. value), 0) total_value FROM Customers a LEFT JOIN Orders b ON a. Oracle supports operating systems such as Windows, Linux, Solaris, HP-UX, OS X, etc. Return to all comments → Among several electronic database Management System, the 2 most well-liked and widely used are Oracle and SQL Server. Easy SQL (Advanced) Max Score: 25 Success Rate: 97. Many thanks, Mike SQL (Intermediate) It includes complex joins, unions, and sub-queries. dual is an in-memory table. Skills. id = cu. You can break this answer by switching the orders for customers 102 and 103. SELECT C. sql & 2. Modified 2 years, Cannot reproduce this behavior in SQL Server 2016 - works as anyone would have guessed patients is the table name which has the first name and last name column. rf, ttc. SalesOrderDetail SOD on SOD. This arrangement allows multiple columns of IMAGE or Problem. city_name, pr. Here's their snippet that won't seem to run for me in Chrome. For starters, the question was in the style: there is this feature in Oracle that is being missed in SQL Server and what is the recommended approach. SELECT customer_name, COUNT(DISTINCT product_ID) as products_count FROM customer_table INNER JOIN orders_table ON customer_table. e. Can anyone help? There were a number of contests where participants each made number of attempts. The bitwise AND of all long integers in the inclusive range between and can be expressed as , where is the bitwise AND operator. With HackerRank and Oracle Recruiting, customers can standardize their global technical recruiting The quickest path to approach companies that use Oracle lies in incorporating target-specific information into promotional efforts. id If you want all customer and product combinations, then I would suggest: select c. The result includes the names of the city and product, as well as the total amount spent on the product, rounded to 2 decimal places. 2 IMAGE and TEXT Data Types (Binary Large Objects). category AND a. Sqlserver vs. In SQL Server SET NOCOUNT affects the behaviour even in non-interactive scenarios. Marco and Alberto have worked with Analysis Services, Power BI and Power Pivot since the first Optimized for Oracle software. Tested it on SQL Server - works fine. sale_id, p. *[^aeiou]$','i') and regexp_like(city,'^[^aeiou]\\w+[^aeiou]$','i'); . system_type_id) as DataType, t2. You are viewing a single comment's thread. ODCI*LIST types as they can hold 32767 items but it is a limitation on SQL functions that their expression list can have a maximum of 999 arguments. product_id = pr. Paneer 4. 2. You'll notice some extra stuff in there to test if the sign of the row is negative. To me learning pl/sql or t/sql is no different than learning any other programming language and you’re always learning something new. If I understand correctly, you are looking for the top 50 sales for customers based on 2011 data - and want to see all years data for those top 50 from 2011, regardless of those customers being in the top 50 for other years. Ask Question Asked 3 years, 5 months ago. Product P LEFT JOIN Sales. digit + d3. CustomerID WHERE EXISTS(SELECT 1 FROM Invoice WHERE CustomerID = I. You switched accounts on another tab or window. GitHub community articles Products Without Sales(solution I have an attendance table for the employees like the following ID Employee-ID Date Coming-time Leaving-time Break(in hours) 1 1 2016-01-01 08:00:00 18: This repository contains MYSQL solutions of HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test . Write a query that prints a list of employee names (i. 2821 verified user reviews and ratings of features, pros, cons, pricing, support and more. 400 4. here I want to combine the first and last names in the new column, which is the full name so I'm using CONCAT. - DaveSV/HackerRank-SQL-Intermediate-Certificate The explanation section of the problem states: The results of the second query are ascendingly ordered first by number of names corresponding to each profession (2 <= 2 <= 3 <= 3), and then alphabetically by profession (doctor <= singer, and actor <= professor). name from ( select substr( csv , instr(csv,',',1,lev) + 1 , instr(csv,',',1,lev+1 )-instr(csv,',',1,lev)-1 ) lstid from (select ','||'1,2,3,4,5'||',' csv from dual Watch all Easy Hackerrank SQL Problems solved in this video. CREATE TABLE #orders(OrderId int identity(1,1), CustNum int, Orderdate date) -- using system columns to populate demo data (I'm lazy) INSERT INTO #orders(CustNum,Orderdate) SELECT system_type_id, DATEADD(month,column_id*-1,GETDATE()) FROM sys. Query the number of ocurrences of each Hackerrank Intermediate SQL certification solutions with basic SQL quarries, Sub quarries and Aggregation functions. We segment the hosted information on Oracle customers comprehensively Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. We use cookies to ensure you have the best browsing experience on our website. Name To further gain more knowledge about joins, kindly visit the link below: Visual Representation of SQL Joins; Result, i do this select distinct city from station where regexp_like(city,'^[^aeiou]. SELECT CUSTOMER_NAME, Y. Sep 25, 2023 Marco Russo & Alberto Ferrari Power Pivot, and SQL Server Analysis Services. Calculating Sales Count. count_rf, tg. CustomerName, I. Download the necessary Oracle Instant Client packages: Basic, ODBC, and SQL*Plus (optional) b. A common use of Oracle's ROWID is to provide a (somewhat) stable method of selecting rows and later returning to the row to process it (e. Thomson Data offers just that. Compare Oracle Database vs Microsoft SQL Server. Finding the best selling item for each of your best customers in SQL. quantity), 0) AS quantity FROM customer c LEFT JOIN invoice i on c. You can construct and populate a list in PL/SQL with more than 1000 items and pass it to the SQL statement and it will work db<>fiddle and you can pass more than 1000 select ci. ORACLE database : Y ORACLE table name : PS. Status. maxPrice Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Write better code with AI Security. Products. Find and fix vulnerabilities Actions Customer Stories Partners Executive Insights Open Source GitHub Sponsors AmareshMuddebihal / HackerRank-SQL List Customer and Product Without Sale Using the UNION operator, in one list return all customers who do not have an invoice and all products that were not sold. Category ,fill. Customer Spending. The tables I'm using are: Customers. 0 Several of the answers above will work around the lack of a direct reference to a specific row, but will not work if changes occur to the other rows in a table. Whereas SQL Server supports only windows and Linux operating systems. 3. I do not own or make these questions. But I'm struggling to figure out how to get highest revenue month-year from this data. poicnx dln pgd gnmawy nmijpcx clf jugt xai mseklzo nlch